ex. 1: percent composition of AgOH (assume there is 1mol)
total MM (molar mass): 107.9 + 19.0 + 1.0 = 127.9
MM of Ag: 107.9 (same numerical value as the atomic mass)
MM of O: 16.0
MM of H: 1.0
% Ag: 107.9g/mol / 127.9g/mol x 100% = 84%
% O: 19.0g/mol / 127.9g/mol x 100% = 15%
% H: 1.0g/mol / 127.9g/mol x 100% = 1%
Check: 84% + 15% + 1% = 100%*
*the percentages should add up to or very close to 100%
ex. 2: percent composition of CO2 (assume there is 1mol)
total MM: 12.0 + 16.0(2) = 44.0g/mol
MM of C: 12.0g/mol
MM of O: 32.0g/mol
% C: 12.0g/mol / 44.0g/mol x 100% = 27.3%
% O: 32.0g/mol / 44.0g/mol x 100% = 72.2%
Check: 27.3% + 72.2% = 100%
ex. 5: percent composition of O in Cu2CO3
total MM: 123.5g/mol
MM of O: 48.0g/mol
% O: 48.0g/mol / 123.5g/mol x 100% = 39%
ex. 4: a compound contains 5.1 g of Cl, 22.0g of c, an unknown mass of O, & the total mass is 44.1g. Calculate % composition.
Mass of O: 44.1g-5.1g-22.0g = 17.0g
% Cl: 5.1g / 44.1 g x 100% = 11.6%
% O: 17.0g / 44.1g x 100% = 38.6%
% C: 22.0g / 44.1g x 100% = 49.9%
Check: 11.6% + 38.6 % + 49.9% = 100.1 %
Links to get you started:
http://chemistry.about.com/od/workedchemistryproblems/a/mass-percent-worked-problem.htm
http://www.ausetute.com.au/percentc.html
http://www.youtube.com/watch?v=qzUMKWhWKm8 (THE BEST LINK!)
http://www.youtube.com/watch?v=CSuZVJ8TA40&feature=related
No comments:
Post a Comment